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If the actual conductance of an axon's ion channel is 10 $\mathrm{pS}$ and the peak current during a squid axon's action potential (the electrical disturbance that propagates down the axon is 5 $\mathrm{mA} / \mathrm{cm}^{2}$ what is the density of channels in the membrane? Assume that the voltage across the membrane is 50 $\mathrm{mV}$.A. 1$/ \mathrm{m}^{2}$ B. 100$/ \mathrm{cm}^{2}$ C. 1$/ \mathrm{cm}^{2}$ D. 100$/ \mu \mathrm{m}^{2}$

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Physics 102 Electricity and Magnetism

Chapter 19

Current, Resistance, and Direct-Current Circuit

Electric Charge and Electric Field

Gauss's Law

Electric Potential

Capacitance and Dielectrics

Current, Resistance, and Electromotive Force

Direct-Current Circuits

Electromagnetic Induction

Rutgers, The State University of New Jersey

Simon Fraser University

University of Winnipeg

Lectures

10:31

A capacitor is a passive t…

18:38

In physics, electric flux …

04:16

In a simple model of an ax…

01:09

Assume that a typical open…

02:52

If we model the pore of a …

01:48

The potential difference a…

01:18

An axon has the outer part…

02:19

(a) Calculate the capacita…

03:32

The membrane that surround…

01:01

(1) What is the magnitude …

01:31

(I) What is the magnitude …

02:28

Transmission of nerve impu…

05:54

Axon capacitance The long …

The membrane surrounding a…

01:03

Nerve cells transmit elect…

03:08

A cell membrane has a surf…

01:44

An axon is the relatively …

04:00

Cell membranes across a wi…

03:14

03:46

Suppose that the resistanc…

07:16

Energy stored in axon elec…

02:33

(III) During an action pot…

we are giving the conductor's off. Each Hi Katana is E Channel is 10 Pikus Indians. It is 10 in total, far minus well, Simeon's Justin far minus low and Samir. I know that resistance is won by conduct ins, so that's 10 by 11 homes offer assistance. You know that current is four days. Five assistants were given the world ages 50,000,000 world. So, like, if anybody came by 11 0 we know that Emelia told simply Intar minus three World excuse us, or we can just simply with us is. But regardless, we can't fire into 10 minus 10,000,000 peers. Now we know that this is the amount ofthe current for channel and we are given that current first unit surface area is 5,000,000 peers are centimeter square. Notice that this is the reason why I left my units as 1,000,000 amperes so that you I was sort of the same mind. They'll cancel out easily. So this is the total current. The total current density. Hence the density off the child is simply the areal density off the channels. 5,000,000 amperes. Why send even a square he wanted bhai, They're covering for each other 5 to 10 farm anistan 1,000,000 ampere for China. As you can see, the unit's become Channel four Centimeter Square, which is exactly what we need. This is a very good best off seeing if you have done the problem. Lucien's on disk uses 10 Part 10. The person doing the square. So this is your final answer. I just noticed that 10 part in channel for city. We just queer is not getting the options, but options for seams possible. So if we can work its one centimeter into millimeter micrometers, we know that one centime Justin Palmer is for my from meters on. This gives us time for minus two by I'm certain part 10 divided by I'm sorry, this isn't my place for And Part four square, which is 10 minus two. I'm certain part less to bless and our place to channel for my four meters square which is option the this is your answer. But before we and is this up, let's think our why did you write it like this? We want the number ofthe channels or given surface area on me No current for channel. So this is the amount ofthe current in each shadow in each channel. On this is the amount of current in the whole area. So if you simply want how many channels are there in this whole area, we simply divide this all current divided by the current in the channel. It's like doing if you have If you take a chessboard on DH, you have a bunch of squares. If you want to find out how many squares are there, you simply take the area off the whole board on, divided by the area off a small square. Similarly, you know this kind of division.

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