Question
If the allowable tensile stress for wires $A B$ and $A C$ is $\sigma_{\text {allow }}=200 \mathrm{MPa}$, determine the required diameter of each wire if the applied load is $P=6 \mathrm{kN}$
Step 1
The sum of the forces in the y-direction must be zero. This gives us the equation: \[-6 + F_{AB} \cos(45) + F_{AC} \sin(53.13) = 0\] Solving this equation gives us: \[0.707 F_{AB} + 0.8 F_{AC} = 6\] Show more…
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