00:01
We have this cube here which is pushed with the force at the point c, and we define the time that it takes for this cube to complete one full revolution, knowing that it can rotate about this diagonal from point a to point b.
00:18
And we know that the mass, so the mass, mass m prime, this is the mass of one side of this cube, which we can get by taking the total mass and dividing it by six.
00:33
And the mass of one side of the cube is given as 8 kilograms.
00:43
So 8 kilograms.
00:49
And when we're solving this problem, we're going to assume that the x, y, and z axis are all perpendicular to the faces of this cube.
01:01
So we're going to start by finding what the moment of inertia is for a side that's perpendicular to the x axis.
01:11
So we'll call that i of x1.
01:13
So i of x1, and we can write that as 1 over 6 times m prime times a square.
01:29
And next we'll write the moment of inertia for a side that's perpendicular to the y or z axis with respect to the x axis.
01:42
So we'll call that i of x2, and that's going to be equal to 1 over 12 plus 1 over 4 times.
01:54
M prime times a squared and we can simplify this as 1 over 3 times m prime times a squared so now to get the moment of inertia about the x -axis we can take these two terms here and take the summation of them so to write that i of x we're going to write that as two times i of x one since there are two sides that are perpendicular to the x -axis, and then plus four times i of x2, since there's four sides that are perpendicular to either the y or z -axis.
02:50
So now we can just plug in those values.
02:56
And we're going to write that as 1 over 6 times m over 6 times a squared, plus 4 times 1 over 3 times m over 6 times a squared.
03:15
And we can simplify this to 5 over 18 times m times a squared...