Differentiating both sides with respect to $x$, we get
\[n x^{n-1} y + x^n \frac{dy}{dx} = 0.\]
This can be rewritten as
\[\frac{dy}{dx} = -n \frac{y}{x}.\]
At point $P$, we have
\[\frac{dy}{dx} \bigg|_{(x_1, y_1)} = -n \frac{y_1}{x_1} = -n \frac{a^n}{x_1^n} = -n
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