Question
If the average density of matter in the universe is $3 \times 10^{-31} \mathrm{kg} / \mathrm{L}$ what is the total mass of the universe within our current cosmic horizon? How many galaxies of $10^{11} M_{\odot}$ does this represent?
Step 1
First, we need to find the volume of the universe within our current cosmic horizon. The cosmic horizon is the maximum distance from which we can receive information, and it is approximately 46.5 billion light-years (or 4.4 × 10^26 meters) in radius. Show more…
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