If the binding energy Per nucleon in ${ }_{3}^{7} \mathrm{Li}$ and ${ }^{4}{ }_{2}$ He nuclear is $5.6 \mathrm{MeV}$ and $7.06 \mathrm{MeV}$ respectively, then in the reaction $\mathrm{P}+{ }_{3} \mathrm{Li} \rightarrow 2\left({ }_{2}^{4} \mathrm{He}\right)$ (P here retrent Proton) energy of Proton
must be
(A) $1.46 \mathrm{MeV}$
(B) $39.2 \mathrm{MeV}$
(C) $17.28 \mathrm{MeV}$
(D) $28.24 \mathrm{MeV}$