The given equation is $9x^2 + 16y^2 - 18x - 64y + 17 = 0$. We can rewrite this as $(9x^2 - 18x) + (16y^2 - 64y) = -17$.
To complete the square, we need to add and subtract $(\frac{18}{2(9)})^2 = 1$ for the x terms and $(\frac{64}{2(16)})^2 = 4$ for the y terms.
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