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If the contraction of the left ventricle of the heart lasts 250 $\mathrm{ms}$ and the rate of flow of the blood in the aorta (the large artery leaving the heart) is $1.0 \mathrm{m} / \mathrm{s},$ what is the average acceleration of a red blood cell as it leaves the heart?A. 250 $\mathrm{m} / \mathrm{s}^{2}$B. 25 $\mathrm{m} / \mathrm{s}^{2}$C. 40 $\mathrm{m} / \mathrm{s}^{2}$D. 4.0 $\mathrm{m} / \mathrm{s}^{2}$

4.0 $\mathrm{m} / \mathrm{s}^{2}$

Physics 101 Mechanics

Chapter 2

Motion along a Straight Line

Physics Basics

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Rutgers, The State University of New Jersey

Hope College

University of Sheffield

McMaster University

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so here the average acceleration in the ex direction would be equal to the change in velocity in the ex direction divided by the change in time. This would be equal to 1.0 meters per second minus zero meters per second and then divided by 00.250 seconds. And this would be equal to 4.0 meters per second squared. So this means that the correct answer would be answer choice D. That is the end of the solution. Thank you for watching.

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