Question
If the curves $x^{2}+y^{2}-8|x|-9=0$ and $y=|x|+c$ do not intersect, then(a) $c<-4-5 \sqrt{2}$ or $c>-4+5 \sqrt{2}$(b) $-4-5 \sqrt{2}<\mathrm{c}<-4+5 \sqrt{2}$(c) $-5 \sqrt{2}<\mathrm{c}<5 \sqrt{2}$(d) $-4<c<4$
Step 1
The equation \( x^{2} + y^{2} - 8|x| - 9 = 0 \) can be analyzed by considering the cases for \( |x| \). This gives us two cases: \( x \geq 0 \) and \( x < 0 \). Show more…
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