Question
If the electric ficld strength in air exceeds $3.0 \times 10^{6} \mathrm{N} / \mathrm{C}$ , the air becomes a conductor. Using this fact, determine the maximum amount of charge that can be carricd by a metal sphere 2.0 $\mathrm{m}$ in radius. (See the hint in Problem 40.)
Step 1
Step 1: We know that the electric field strength is given by the formula $E = \frac{K_eQ}{r^2}$, where $E$ is the electric field strength, $K_e$ is the electric constant, $Q$ is the charge, and $r$ is the radius of the sphere. Show more…
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If the electric field strength in air exceeds $3.0 \times 10^{6} \mathrm{~N} / \mathrm{C}$, the air becomes a conductor. Using this fact, determine the maximum amount of charge that can be carried by a metal sphere $2.0 \mathrm{~m}$ in radius.
Air becomes a conductor when the electric field strength exceeds $3.0 \times 10^{6} \mathrm{N} / \mathrm{C}$. Determine the maximum amount of charge that can be carried by a metal sphere $2.0 \mathrm{m}$ in radius.
Air becomes a conductor when the electric field strength exceeds 3.0x10^6 N/C. Determine the maximum amount of charge that can be carried by a metal sphere 2.0 m in radius.
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