If the electric field associated with a radiation of frequency $10 \mathrm{MH} z$ is $\mathrm{E}=10 \sin (\mathrm{kx}-\omega \mathrm{t}) \mathrm{mV} / \mathrm{m}$ then its energy density is
$\mathrm{Jm}^{-3}\left(\varepsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} \mathrm{~N}^{-1} \mathrm{~m}^{-2}\right)$
(A) $4.425 \times 10^{-10}$
(B) $6.26 \times 10^{-14}$
(C) $8.85 \times 10^{-16}$
(D) $8.85 \times 10^{-14}$