Question
If the emitter current of a transistor is $8 \mathrm{~mA}$ and $I_{B}$ is $1 / 100$ of $I_{C}$, determine the levels of $I_{C}$ and $I_{B}$.
Step 1
So, we can write the equation: I_E = I_B + I_C We are given that I_E = 8 mA and I_B = 1/100 * I_C. We can substitute the value of I_B in terms of I_C into the equation: 8 mA = (1/100 * I_C) + I_C Now, we can solve for I_C: 8 mA = (1/100 * I_C) + I_C 8 mA = Show more…
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If the emitter current of a transistor is 8 mA and IB is 1/100 of IC, determine the levels of IC and IB
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