00:01
We are given an equation which is a n x to the power n plus a n minus 1 x to the power n minus 1 plus dot dot plus a 1x that is equal to 0.
00:15
And it is said that this has a positive root x equal to alpha.
00:21
It has a root root which is given by x equal to alpha.
00:26
And now we need to comment on the root of the equation and a n x to d power n minus 1 plus n minus 1 a n minus 1 x2 0 plus dot dot dot plus a 1 equal to 0 so first let let a function f x which is a n x2d power n plus a n minus 1 x to d power n minus 1 plus dot dot dot plus a 1x now differentiate this with respect to x we get n a n x to d power n minus 1 plus n minus 1 a n minus 1 x to the power n minus 2 plus dot dot plus a 1 and we need to comment on the root of this equation so let's suppose this is equation first this is equation second so from equation first equation first we can say that if if if x equal to 0, then then fx will be equal to 0.
01:33
If you put x equal to 0 in this, then the value of fx comes out to be 0.
01:39
That means 0 is the root of this function or this equation.
01:45
And a root which is x equal to alpha is already given to us, is already given to us? so, at x equal to alpha, fx again 0, that means 0 and alpha are the two roots.
02:02
0 and alpha are the two roots of equation first, of equation first...