00:01
I have been in this plane here containing these lines.
00:04
Now this plane here is parallel to we have the equation.
00:10
So this is, first we have two planes here.
00:13
This plane and this plane, the line of intersection of these two planes.
00:16
So we're given here the information is the question of plane containing two lines is parallel to the line of intersection.
00:23
So the question of the plane here, the plane contained this two lines.
00:25
It is parallel to the line of intersection of the two planes.
00:33
And it is given as.
00:34
The equation of that plane is a x plus b y so it's given as a x plus b y plus p z plus d that is equal to zero that's the equation of plane we need to find out then modulus a plus b plus so this i'm again repeating this plane is parallel to here the line of intersection what we can do here so first we just find the equation of plane containing these two lines so so, let's say, pi 1, so equation of pi 1 is given as x negative y, negative z, negative 4 plus lambda x, positive y, positive to z, negative 4, that is equal to 0.
01:21
Equation 1 now, if you see here, we'll find out a vector here that is parallel to this line.
01:27
So what we can do, we just take the normal from here, normal to this plane, and normal from this here, normal to this plane here we have...