Question
If the equation of a wave in a string having linear mass density $0.04 \mathrm{~kg} \mathrm{~m}^{-1}$ is given by $\mathrm{y}=0.02$ $\sin [2 \pi\{1 /(0.04)\}-\{\mathrm{x} /(0.50)\}]$, then the tension in the stringis $\ldots \ldots \ldots \ldots$ N. (All values are in $\mathrm{mks}$ )(A) $6.25$(B) $4.0$(C) $12.5$(D) $0.5$
Step 1
02 \sin[2\pi(1/0.04) - (x/0.50)]$. We can compare this with the general wave equation $y = A \sin[2\pi(t/T) - (x/\lambda)]$ where $A$ is the amplitude, $T$ is the period, and $\lambda$ is the wavelength. Show more…
Show all steps
Your feedback will help us improve your experience
Supratim Pal and 84 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The equation of a wave on a string of linear mass density $0.04 \mathrm{~kg} \mathrm{~m}^{-1}$ is given by $y=0.02(m) \sin \left[2 \pi\left(\frac{t}{0.04(s)}-\frac{x}{0.50(m)}\right)\right]$ The tension in the string is (A) $4.0 \mathrm{~N}$ (B) $12.5 \mathrm{~N}$ (C) $0.5 \mathrm{~N}$ (D) $6.25 \mathrm{~N}$
The equation of a wave of a string of linear mass density $0.04 \mathrm{~kg} \mathrm{~m}^{-1}$ is given by, $y=0.02(\mathrm{~m}) \mathrm{sin}$ $\left[2 \pi\left(\frac{t}{0.04(s)}-\frac{x}{0.50(m)}\right)\right]$. The tension in the string is: (a) $4.0 \mathrm{~N}$ (b) $12.5 \mathrm{~N}$ (c) $0.5 \mathrm{~N}$ (d) $6.25 \mathrm{~N}$
BEHAVIOUR OF PERFECT GAS AND KINETIC THEORY
Waves
The equation of the wave on a string of linear mass density $0.04 \mathrm{kgm}^{-1}$ is given by $$ y=0.02(\mathrm{~m}) \sin \left[2 \pi\left(\frac{t}{0.04(\mathrm{~s})}-\frac{x}{0.50(\mathrm{~m})}\right)\right] $$ The tension in the string is (a) $6.25 \mathrm{~N}$ (b) $4.0 \mathrm{~N}$ (c) $12.5 \mathrm{~N}$ (d) $0.5 \mathrm{~N}$
Round 2
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD