Question
If the equations $2 x-y-z=0, k x-3 y+2 z=0$ and $-3 x+2 y+k z=0$ have a non-zero solution, then the value of $k$ is(A) 2(B) 1(C) 7(D) Both 1 and 7
Step 1
So, we form the determinant as follows: \[ \begin{vmatrix} 2 & -1 & -1 \\ k & -3 & 2 \\ -3 & 2 & k \\ \end{vmatrix} = 0 \] Show more…
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