Question
If the equations $x^{2}-p x+q=0, x^{2}-r x+s=0$ have a common root which is the harmonic mean between their other two roots, prove that(i) $(\mathrm{q}-\mathrm{s})^{2}=(\mathrm{p}-\mathrm{r})(\mathrm{qr}-\mathrm{ps})$(ii) $p s(3 q+s)=q r(3 s+q)$
Step 1
Then, we have the following equations from the given quadratic equations: \begin{align*} \alpha^2 - p\alpha + q &= 0 \quad \text{(1)} \\ \alpha^2 - r\alpha + s &= 0 \quad \text{(2)} \end{align*} Show more…
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