Question
If the function $p=p(T, v)$ is an equation of state, is $(\partial p l \partial T)_{0}$ a property? What are the independent variables of $(\partial p / \partial T)_{v} ?$
Step 1
We have a function p(T, v) which represents an equation of state. This means that the function p relates the pressure (p) to the temperature (T) and specific volume (v) of a substance. Show more…
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If the function $p=p(T, v)$ is an equation of state, is $(\partial p / \partial T)_{v}$ a property? What are the independent variables of $(\partial p / \partial T)_{v} ?$
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If $U=U(V, T)$ and $p=p(V, T)$ are functions of $V$ and $T$ and if $H=U+p V$, show that $\left(\frac{\partial H}{\partial T}\right)_{p}-\left(\frac{\partial U}{\partial T}\right)_{V}=\left[\left(\frac{\partial U}{\partial V}\right)_{T}+p\right]\left(\frac{\partial V}{\partial T}\right)_{p}$
(a) Calculate $(\partial P / \partial V)_{T}$ and $(\partial P / \partial T) v$ for a gas that has the following equation of state: \[P=\frac{n R T}{V-n b}\] (b) Show that $\left(\partial^{2} P / \partial V \partial T\right)=\left(\partial^{2} P / \partial T \partial V\right) .$ These are referred to as mixed partial derivatives.
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