00:01
In this question we have given a solid balls that rolls smoothly from rest and we have to find the horizontal distance the ball travels from point a.
00:12
So first of all i am drawing the diagram for this given cution so this is the track we have given and this is the light height we have given so this height is capital h this is the height small edge and this point is point a we have given and let the ball finally reaches this point and this is given by let b.
00:45
Now we have given data for this question that is capital h is 6 meters small h is given to us that is 2 meter and we know that for solid ball moment of inertia is given by 2 by 5 of mr square.
01:03
Now that this is point 1 and this is at 0 .2 so energy at 1 is given by that is u1 is mgh and kinetic energy at this point is 0 and at this point we can say that final potential energy is mgh and kinetic energy at this point is given by that is half of mv square plus this is due to translational and this is due to rotational so by energy conservation we can say that energy at that total energy at 1 is equal to total energy at 2.
02:03
So at 1 there is kinetic that is potential energy at 1 plus kinetic energy at 1 is equal to potential energy at 2 and kinetic energy at 2.
02:12
Now put all the data in this equation.
02:14
So this is mg h is equal to this is m g into small h plus half of mv square plus this is half of i omega square.
02:28
Now further we can say that this can be written as mgh is equal to this is m gh plus half of mv square plus this is half i is 2 by 5 of mr square and omega is given by v square by r square.
02:43
After solving this we get this is 7 by 10 of v square is equal to this is g into h minus small h finally from here we get the value of v and this will comes out to be 10 by 7 into g capital h minus small h root over.
03:01
Now put all the data in this equation...