Question
If the hands of a clock coincide every 65 minutes (true time), in $24 \mathrm{hrs}$ the clock will gain(a) $10 \frac{10}{143}$ mins.(b) $9 \frac{12}{143}$ mins.(c) $11 \frac{12}{143}$ mins.(d) $12 \frac{10}{143} \mathrm{mins}$.
Step 1
In a perfect clock, the hands coincide every 60 minutes. Show more…
Show all steps
Your feedback will help us improve your experience
Hubert Agamasu and 66 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Select the correct alternative from the given choices. At what time between 9 and 10 O'clock, will the two hands of the clock coincide? (A) $43 \frac{3}{11}$ minutes past 9 O'clock (B) $45 \frac{6}{11}$ minutes past 9 O'clock (C) $49 \frac{1}{11}$ minutes past 9 O'clock (D) $49 \frac{6}{11}$ minutes past 9 O'clock
Reasoning
Clocks and Calenders
The linear velocity of tip of hours hand of a clock, which is $5 \mathrm{~cm}$ long is (a) $\frac{\pi}{120 \times 60} \mathrm{~ms}^{-1}$ (b) $\frac{\pi}{120 \times 60 \times 60} \mathrm{~ms}^{-1}$ (c) $\frac{\pi}{120} \mathrm{~ms}^{-1}$ (d) $\frac{\pi}{60 \times 60 \times 60} \mathrm{~ms}^{-1}$
Rotational Motion
Round 2
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD