Question
If the harmonic mean of two numbers is 4 and their arithmetic mean $\mathrm{A}$ and geometric mean $\mathrm{G}$ satisfy the relation $2 \mathrm{~A}+\mathrm{G}^{2}=27$, the two numbers are(a) 6,3(b) 5,4(c) $5,-2.5$(d) $-3,1$
Step 1
The harmonic mean of two numbers a and b is given by the formula $\frac{2ab}{a+b}$. So, we have $\frac{2ab}{a+b}=4$. Show more…
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