If the kinetic energy of a particle executing S.H.M. is given by $\mathrm{K}=\mathrm{K}_{0} \cos ^{2} \omega \mathrm{t}$, then the displacement of the particle is given by $\ldots \ldots$
(A) $\left\{\mathrm{K}_{0} / \mathrm{m} \omega^{2}\right\} \sin \omega \mathrm{t}$
(B) $\left\{\left(2 \mathrm{~K}_{0}\right) /\left(\mathrm{m} \omega^{2}\right)\right\}^{1 / 2} \sin \omega t$
(C) $\left\{2 \omega^{2} / \mathrm{mK}_{0}\right\} \sin \omega t$
(D) $\left\{2 \mathrm{~K}_{0} / \mathrm{m} \omega\right\}^{1 / 2} \sin \omega t$