Question
If the length of the chord of the circle, $x^{2}+y^{2}=r^{2}(r>0)$ along the line, $y-2 x=3$ is $r$, then $r^{2}$ is equal to : (a) $\frac{9}{5}$(b) 12(c) $\frac{24}{5}$(d) $\frac{12}{5}$
Step 1
We can rewrite this in slope-intercept form as $y=2x+3$. The slope of this line is $2$, which means the angle it makes with the x-axis is $\tan^{-1}(2)$. Show more…
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If one of the diameters of the circle, given by the equation, $x^{2}+y^{2}-$ $4 x+6 y-12=0$, is a chord of a circle $S$, whose centre is at $(-3,2)$ then the radius of $S$ is: (a) 5 (b) 10 (c) $5 \sqrt{2}$ (d) $5 \sqrt{3}$
If one of the diameters of the circle, given by the equation, $x^{2}+y^{2}-4 x+6 y-12=0$, is a chord of a circle $S$, whose centre is at $(-3,2)$, then the radius of $S$ is (A) 10 (B) $5 \sqrt{2}$ (C) $5 \sqrt{3}$ (D) 5
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