If the outer electron in lithium moves in the $n=2$ Bohr orbit, the effective nuclear charge would be $Z_{\text {eff }} e=1 e,$ and the energy of the electron would be $-13.6 \mathrm{eV} / 2^{2}=-3.4 \mathrm{eV}$. However, the ionization energy of lithium is $5.39 \mathrm{eV},$ not $3.4 \mathrm{eV}$ Use this fact to calculate the effective nuclear charge $Z_{\text {eff }}$ seen by the outer electron in lithium. Assume that $r=4 a_{0}$ for the outer electron.