Question
If the peak electric field due to a star whose radius is twice that of he Sun is $44.0 \mathrm{~V} / \mathrm{m}$ at a distance of $15 \mathrm{AU}$, what is its temperature? Treat the star as a blackbody.
Step 1
For a star, the surface area is $A = 4\pi R^2$, where $R$ is the radius of the star. So, we can write the power as $P = \sigma 4\pi R^2 T^4$. Show more…
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