00:01
This question asks a few questions within the question.
00:06
At first, asks that if we were trying to determine if a point 2 -3 was on an equation of a line, the equation specifically in x and y, then the equation is satisfied when we replace x by 2 and y by 3.
00:32
Here we are given the equation of a line 2y equals x plus 1.
00:40
We were asked if the point 2 .3 is on this line.
00:46
To answer that question, we would substitute in.
00:50
The values is given.
00:52
We put the 2 in for x, the y in for 3.
00:56
And when we evaluate here, we get that 6 equals 3, which clearly is not true.
01:02
So the ordered peer is not on the graph.
01:15
We are then asked to complete this table and sketch the graph.
01:24
This is going to be a little bit easier if we rework with this equation.
01:30
I am going to substitute into y equals one -half x plus one -half.
01:40
So here when we substitute in negative two for, x.
01:45
You don't really have room to show that.
01:47
I could show it over here...