If the primal problem is constrained by equations instead of inequalities-Minimize cx subject to $A x=b$ and $x \geq 0$-then the requirement $y \geq 0$ is left out of the dual: Maximize yb subject to $y A \leq c$. Show that the one-sided inequality $y b \leq c x$ still holds. Why was $y \geq 0$ needed in equation (1) but not here? This weak duality can be completed to full duality.