Question
If the relative humidity is 90.0\% on a muggy summer morning when the temperature is $20.0^{\circ} \mathrm{C},$ what will it be later in the day when the temperature is $30.0^{\circ} \mathrm{C},$ assuming the water vapor density remains constant?
Step 1
Given that the relative humidity is 90.0\% at a temperature of $20.0^{\circ} \mathrm{C}$, we can calculate the actual water vapor density (D) using the formula: \[D = \frac{RH}{100} \times QW_{20}\] where $RH$ is the relative humidity and $QW_{20}$ is the Show more…
Show all steps
Your feedback will help us improve your experience
Zulfiqar Ali and 95 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If the relative humidity is 90.0% on a muggy summer morning when the temperature is 20.0ºC , what will it be later in the day when the temperature is 30.0ºC , assuming the water vapor density remains constant?
Late on an autumn day, the relative humidity is 45.0\% and the temperature is $20.0^{\circ} \mathrm{C}$. What will the relative humidity be that evening when the temperature has dropped to $10.0^{\circ} \mathrm{C}$ assuming constant water vapor density?
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD