Question
If the roots of $\mathrm{x}^{2}+(\mathrm{k}-1) \mathrm{x}=2 \mathrm{k}+1$ are equal, value of $\mathrm{k}$ is(a) 5, 1(b) $5,-1$(c) $-5,-1$(d) $-5,1$
Step 1
We can rewrite this equation in the standard form of a quadratic equation $ax^{2}+bx+c=0$ as $x^{2}+(k-1)x-(2k+1)=0$. Show more…
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