Question
If the roots of the equation $x^{2}-2 a x+a^{2}+a-3=0$ are real less than 3 , then:(A) $a<2$(B) $2 \leq a \leq 3$(C) $3<a \leq 4$(D) $a>4$
Step 1
The discriminant is given by $b^{2}-4ac$ where $a$, $b$ and $c$ are the coefficients of the quadratic equation. In this case, $a=1$, $b=-2a$ and $c=a^{2}+a-3$. So, the discriminant is $(-2a)^{2}-4(1)(a^{2}+a-3)$. Show more…
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