If the sides $\mathrm{a}, \mathrm{b}, \mathrm{c}$ of $\triangle \mathrm{ABC}$ are in GP where $\log \mathrm{a}-\log 2 \mathrm{~b}, \log 2 \mathrm{~b}-\log 3 \mathrm{c}, \log 3 \mathrm{c}-\log \mathrm{a}$ are in $\mathrm{AP}$, then the sides $\mathrm{a}$,
b, c are in the ratio
(a) $4: 6: 9$
(b) $9: 4: 6$
(c) $9: 6: 4$
(d) $3: 6: 8$