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If the spring constant of a simple harmonic oscillator is doubled, by what factor will the mass of the system need to change in order for the frequency of the motion to remain the same?

By the factor of 2

Physics 101 Mechanics

Physics 103

Chapter 16

Oscillatory Motion and Waves

Periodic Motion

Wave Optics

Cornell University

Hope College

University of Winnipeg

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so we can say that the expression for frequency is equaling one over to pie multiplied by the square root of the spring constant divided by the mass. And this is equally constant because we want the frequency to stay constant. And so we convince a case of one divided by I'm someone would be equal in case of two divided by amps. Up to now, we can then say that Kay, divided by M sub one, is equaling. If you k divided by am some too. And so Kay's cancel out and we can essentially say that then m sub two is equaling two times I'm someone. So essentially, if the spring constant is doubled, this means that the mass also needs to be doubled in order to maintain a constant the loss of constant frequency. So this would be our final answer. We're essentially the masses again doubled in order to keep a constant frequency. That is the end of the solution. Thank you for

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