Question
If the third equation were $x+3 y+3 z+4=0$ and not as given, then for unique solution,(a) $\mathrm{p}=4 ; \mathrm{q}=3$(b) $\mathrm{p}=6 ; \mathrm{q}=4$(c) $p \neq 6 ; q \neq 3$(d) $\mathrm{p}=6 ; \mathrm{q}=3$
Step 1
Step 1: The given system of equations is: \begin{align*} 2x + py + 6z &= 8 \\ x + 2y + qz &= 5 \\ x + 3y + 3z &= -4 \end{align*} Show more…
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