Question
If the titration of a $25.0-\mathrm{mL}$ sample of acetic acid requires $34.45 \mathrm{~mL}$ of $0.100 \mathrm{M}$ calcium hydroxide, what is the molarity of the acid?$2 \mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)+\mathrm{Ca}(\mathrm{OH})_{2}(a q) \longrightarrow$$$\mathrm{Ca}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l)$$
Step 1
We do this by dividing the given volume by 1000. So, the volume of acetic acid is $25.0 \, \text{mL} = 0.025 \, \text{L}$ and the volume of calcium hydroxide is $34.45 \, \text{mL} = 0.03445 \, \text{L}$. Show more…
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