00:02
This question, first of all, we will determine the velocity as a function of displacement.
00:07
So from the graph, we can write that v equals to 20 minus 0 divided by 0 minus 30 multiplied by s plus 20, okay, as we have two known points on the length.
00:18
So from here, after solving, we get minus 2 by 3 as plus 20.
00:23
Okay.
00:24
And now the acceleration can be obtained from the relations, which is a equals to dv by dt, and it can also.
00:32
Also be written as v dv by d s okay so now from here acceleration a will be equals to v which is this value so minus 2 by 3 s plus 20 and dv by dv by d dv by d s will be equals to minus 2 by 3 so from here after solving acceleration a comes out to be 4 by 9 s minus 40 by 3 so now at at s equals to 15 meter the value of acceleration a which will be equals to 4x9 multiplied by 15 minus 40 by 3.
01:09
So from here acceleration a at a distance as equals to 15 meter will be equals to minus 6 .667 meter per second square.
01:20
Okay.
01:20
So this is the answer for the acceleration of the particle.
01:24
Okay...