If the water falls from a dam into a turbine wheel 19.6 m below, then the velocity of water at

Name: Problem 476, Chapter 4: JEE Physics
Uploaded: 2021-10-10T09:06:02-08:00
Duration: 1 min 6 s
Channel: Narendra Kumar
Description: If the water falls from a dam into a turbine wheel 19.6 m below, then the velocity of water at the turbine is ……(g=9.8 m / s^2) (A) 9.8 m / s (B) 19.6 m / s (C) 39.2 m / s (D) 98.0 m / s

step 1 If the water falls from a dam into a turbine wheel, which is 19 .6 meter below, then the velocit

Question

If the water falls from a dam into a turbine wheel $19.6 \mathrm{~m}$ below, then the velocity of water at the turbine is $\ldots \ldots$ $\left(\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^{2}\right)$ (A) $9.8 \mathrm{~m} / \mathrm{s}$ (B) $19.6 \mathrm{~m} / \mathrm{s}$ (C) $39.2 \mathrm{~m} / \mathrm{s}$ (D) $98.0 \mathrm{~m} / \mathrm{s}$

    If the water falls from a dam into a turbine wheel $19.6 \mathrm{~m}$ below, then the velocity of water at the turbine is $\ldots \ldots$ $\left(\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^{2}\right)$
(A) $9.8 \mathrm{~m} / \mathrm{s}$
(B) $19.6 \mathrm{~m} / \mathrm{s}$
(C) $39.2 \mathrm{~m} / \mathrm{s}$
(D) $98.0 \mathrm{~m} / \mathrm{s}$

JEE Physics

StemEZ 1st Edition

Chapter 4, Problem 476

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Solved by Expert Narendra Kumar

10/10/2021

Step 1

This is due to the conservation of energy principle. The potential energy (PE) is given by the formula PE = mgh, where m is the mass of the water, g is the acceleration due to gravity, and h is the height of the dam. Show more…

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If the water falls from a dam into a turbine wheel $19.6 \mathrm{~m}$ below, then the velocity of water at the turbine is $\ldots \ldots$ $\left(\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^{2}\right)$ (A) $9.8 \mathrm{~m} / \mathrm{s}$ (B) $19.6 \mathrm{~m} / \mathrm{s}$ (C) $39.2 \mathrm{~m} / \mathrm{s}$ (D) $98.0 \mathrm{~m} / \mathrm{s}$

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Key Concepts

Energy Conversion (Potential to Kinetic)

When an object falls, its gravitational potential energy is converted into kinetic energy. This transformation underlies the calculation of the object’s velocity after falling a certain distance, illustrating the principle of energy conservation in a gravitational field.

Kinematics Equations for Free Fall

The kinematics equations, particularly the one expressing v^2 = u^2 + 2gh, mathematically relate the velocity of an object in free fall to the distance it has fallen under gravity. This equation is essential for determining the final speed of an object starting from rest and falling through a known height.

Gravitational Acceleration

Gravitational acceleration is a fundamental physical constant that represents the rate at which an object accelerates towards the Earth due to gravity. It is pivotal in calculations involving free-fall motion and helps determine how quickly velocity increases as an object descends.

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