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If the work required to stretch a spring 1 ft beyond its natural length is 12 ft-lb, how much work is needed to stretch it 9 in. beyond its natural length?

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Calculus 2 / BC

Chapter 6

Applications of Integration

Section 4

Work

Harvey Mudd College

Baylor University

Boston College

Lectures

01:08

If the work required to st…

02:29

02:05

0:00

04:18

Eighteen foot-pounds of wo…

01:57

A force of 10 lb is requir…

02:19

A force of 10 $\mathrm{lb}…

01:44

02:39

Find the natural length of…

00:33

Assume that $10 \mathrm{ft…

Recall the books law that f of x is o k x and the definition of work do equal to f d from 1 to 2 point so plug in the data we have 12 equals to 0 to 1. So that gives us 24 and we're asking the work needed to stretch the spring to 9 inches beyond its natural length, and we know that 1 tistelt inches so what's 9 inches is 0.75 feet. Okay, so the work equals to 0.2 0.7524 x d x escapes from the wall here and that equals to 6.75 feet.

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