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If the work required to stretch a spring 1 ft beyond its natural length is 12 ft-lb, how much work is needed to stretch it 9 in. beyond its natural length?
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Calculus 2 / BC
Chapter 6
Applications of Integration
Section 4
Work
Harvey Mudd College
Baylor University
Boston College
Lectures
01:08
If the work required to st…
02:29
02:05
0:00
04:18
Eighteen foot-pounds of wo…
01:57
A force of 10 lb is requir…
02:19
A force of 10 $\mathrm{lb}…
01:44
02:39
Find the natural length of…
00:33
Assume that $10 \mathrm{ft…
Recall the books law that f of x is o k x and the definition of work do equal to f d from 1 to 2 point so plug in the data we have 12 equals to 0 to 1. So that gives us 24 and we're asking the work needed to stretch the spring to 9 inches beyond its natural length, and we know that 1 tistelt inches so what's 9 inches is 0.75 feet. Okay, so the work equals to 0.2 0.7524 x d x escapes from the wall here and that equals to 6.75 feet.
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