00:01
We assume these three successive terms of geometric progression are a, a -r, and a -r squared.
00:13
Here, r is a common ratio, and since the common ratio is greater than 1, ar is the largest.
00:23
To guarantee that they form the sides of a triangle, the sum of the two sides must be greater than the length of the largest sides.
00:43
And hence this inequality must be satisfied.
00:49
And since a is positive, we can divide both sides by a.
01:00
And now we need to solve this inequality.
01:05
First, we can subtract the left hand side from both sides.
01:10
And first, we solve the left hand side from both sides...