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If two cards are drawn without replacement from an ordinary deck, find the probabilities of the following results.The second is an ace, given that the first is not an ace.

$\frac{4}{51}$

Calculus 2 / BC

Chapter 7

Sets and Probability

Section 5

Conditional Probability; Independent Events

Sequences

Oregon State University

Harvey Mudd College

University of Michigan - Ann Arbor

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Okay, so we want the probability that second is a C given first was not a C. And so then we've taken one court out. So we'll have 51 on the bottom and then since will still have all four aces. Where will be on the top? I can't be divided by anything were simplified, so that's all right.

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