Question
If two soap bubbles of radii $r_{1}$ and $r_{2}\left(>r_{1}\right)$ are in contact, the radius of their common interface is(A) $r_{1}+r_{2}$(B) $\left(r_{1}+r_{2}\right)^{2}$(C) $\frac{r_{1} r_{2}}{r_{2}-r_{1}}$(D) $\sqrt{r_{1} r_{2}}$
Step 1
Step 1: We are given two soap bubbles with radii $r_{1}$ and $r_{2}$ where $r_{2} > r_{1}$. Show more…
Show all steps
Your feedback will help us improve your experience
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If two soap bubbles of equal radii r coalesce then the radius of curvature of interface between two bubbles will be (a) r (b) 0 (c) Infinity (d) 1/2r
The common radius of curvature ' $r^{\prime}$, when two soap bubbles with radii $r_{1}$ and $r_{2}\left(r_{1}>r_{2}\right)$ come in contact, is: (a) $r=\frac{r_{1}+r_{2}}{2}$ (b) $r=\frac{r_{1} r_{2}}{r_{1}-r_{2}}$ (c) $r=\frac{r_{1} r_{2}}{r_{1}+r_{2}}$ (d) $r=\sqrt{r_{1} r_{2}}$
When two soap bubbles of radius $r_{1}$ and $r_{2}\left(r_{2}>r_{1}\right)$ coalesce, the radius of curvature of common surface is (a) $\left(k_{2}-r_{1}\right)$ (b) $\left(r_{2}+r_{1}\right)$ (c) $\frac{5-r_{1}}{r_{15}}$ (d) $\frac{\sqrt{2} r_{1}}{5-n_{1}}$
Properties of Liquids
Round 1
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD