00:01
I'm going to work a problem that's a fairly straightforward application of oms law, which says that voltage is current times resistance, and it's a series circuit, and so remember that the total voltage is going to be equal to the sum of the voltage supplies, not the sum of the work, that's silly, but the sum of the voltage supplies.
00:22
And also that the resistance, the total resistance, is the sum of the resistors.
00:29
If they're hooked up end to end, then it's just a matter of adding that.
00:32
Together.
00:34
So we're going to start looking at the total voltage that's supplied to the circuit and remembering the passive sign convention that the total voltage it's supplied if a power, if the current rather, is moving into the negative terminal out of the positive and so the the larger one is that 12 volts that's going to determine the direction so we have 12 volts and then or on the other side we have that 4 volts and the current is flowing into its positive and so it's being absorbed.
01:06
So the total voltage that we have being supplied to the circuit is 8 volts.
01:12
And then the total resistance is equal to 3 kilo -ooms plus 1 kilo -oam.
01:22
And so it's equal to 4 kilo -ooms.
01:27
So now i can figure out what the current that goes through that circuit at every place in the circuit is.
01:33
That is applying oms law.
01:37
It's equal to the total voltage over the total current...