Question
If $v_{c}(t=2 s)=10 \mathrm{V}$ in the circuit in Fig. $\mathrm{P} 6.17$, find the energy stored in the capacitor and the power supplied by the source at $t=6 \mathrm{s}$
Step 1
The potential across the capacitor is given by $v_{c}(t)=v_{0}+\frac{v_{m}}{RC}t$. Given that $v_{c}(t=2s)=10V$, the capacitance $C=0.5F$, and $t=6s$, we can solve for the potential across the capacitor at $t=6s$ to get $v_{c}(t=6s)=26V$. Show more…
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