Question
If $w_{1} \neq w_{2}$ and $\lambda>0$, show that the set of all points $w$ that satisfy $\left|w-w_{1}\right|=\lambda\left|w-w_{2}\right|$ is a line when $\lambda=1$ and is a circle when $\lambda \neq 1 .\left[\right.$
Step 1
This gives us: \[(w-w_{1})^2=\lambda^2(w-w_{2})^2\] Show more…
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Vectors and the Geometry of Space
Vectors
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