Question
If $x, y, a, b, c$ are $>0$, the maximum value of $x y$ when $a^{2} x^{4}+b^{2} y^{4}=c^{6}$ is(a) $\frac{c^{3}}{2 a b}$(b) $\sqrt{\frac{c^{3}}{2 a b}}$(c) $\frac{c^{3}}{\sqrt{2 a b}}$(d) $\frac{c}{2 \sqrt{a b}}$
Step 1
We can rewrite this equation as $x^{4}=\frac{c^{6}}{a^{2}}- \frac{b^{2} y^{4}}{a^{2}}$. Show more…
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