Question
If $x+10 \equiv 1(\bmod 8)$, then $x$ can be(1) 1(2) 0(3) 6(4) 7
Step 1
This means that $x+10$ leaves a remainder of 1 when divided by 8. Show more…
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Key Concepts
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$x-2=\frac{2 x+8}{5}$ $$\begin{array}{l}{5(x-2)=2 x+8} \\ {5 x-10=2 x+8} \\ {3 x-10=8}\\3 x =18 \\ x =6\end{array}$$
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