Question
If $x^{2}+x+1=0$ and $n$ is a multiple of 3, then the value of $\left(x+\frac{1}{x}\right)\left(x^{2}+\frac{1}{x^{2}}\right)\left(x^{3}+\frac{1}{x^{3}}\right) \ldots . .\left(x^{n}+\frac{1}{x^{n}}\right)$(a) 1(b) 0(c) $2^{n / 3}$(d) $\omega^{2}-1$
Step 1
Step 1: Given the equation $x^{2}+x+1=0$, we know that the roots of this equation are the cube roots of unity, denoted as $\omega$ and $\omega^{2}$. Show more…
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