Question
If you push a crate horizontally with a force of $100 \mathrm{~N}$ across a $10-\mathrm{m}$ factory floor, and the friction force between the crate and the floor is a steady $70 \mathrm{~N}$, how much kinetic energy is gained by the crate?
Step 1
The work done by a force is given by the equation: \[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \] where $\theta$ is the angle between the force and the direction of motion. In this case, the force and the direction of motion are both Show more…
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If you push a crate horizontally with 100 N across a 10-m factory floor and friction between the crate and the floor is a steady 70 N, how much kinetic energy is gained by the crate?
If the force of friction on the crate is a steady 70 N, find the KE gained by the crate.
(a) How much work is done when you push a crate horizontally with 100 $\mathrm{N}$ across a $10-\mathrm{m}$ factory floor? (b) If the force of friction on the crate is a steady 70 $\mathrm{N}$ , show that the KE gained by the crate is 300 $\mathrm{J}$ . (c) Show that 700 $\mathrm{J}$ is turned into heat.
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