00:01
In this question we need to find the value of modulus z if z satisfies modulus z minus 12 upon z minus 8 a iota is equals to 5 by 3 and modulus z minus 4 upon z minus 8 is equals to 1.
00:32
Let's say expression 1 and this was expression 2.
00:39
From expression 2, expression 2, we can make a conclusion that modulus z minus 4 upon z minus 8 is equal to 1 is a perpendicular bisector of the line joining 4 .0 and 8.
01:35
Therefore, the value of x will be equal to 4 plus 8 by 2 and this will be equal to 6.
01:53
Therefore, z can be written as plus iota y.
02:04
Now substitute the value of z in equation 1.
02:08
We get modulus 6 plus iota yv minus 12 upon 6 plus iota y minus 12 upon 6 plus i.
02:28
Iota y minus 8 iota is equal to 5 by 3.
02:38
On further solving we get modulus iota y minus 6 upon plus iota y minus 8 is equals to 5 by 3...