Question
If $z=2\left(\cos 25^{\circ}+j \sin 25^{\circ}\right)$, find $z^{3}$ in polar form.
Step 1
In polar form, a complex number is represented as $r(\cos \theta + j \sin \theta)$, where $r$ is the magnitude and $\theta$ is the angle. In this case, $r=2$ and $\theta=25^{\circ}$. Show more…
Show all steps
Your feedback will help us improve your experience
M Hassan Anwar and 54 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If $z=2\left(\cos 25^{*}+7 \sin 25^{-}\right)$, find $z^{3}$ in polar form.
Complex numbers 2
Test exercise
Find $z_{I} z_{2}$ and $z_{1} / z_{2}$ in the polar form $r e^{i \theta} .$ $z_{1}=5 e^{52^{\circ} i}, z_{2}=2 e^{83^{\circ}}$
Additional Topics in Trigonometry
Complex Numbers and De Moivre’s Theorem
Find $z_{1} z_{2}$ and $z_{1} / z_{2}$ in the polar form $r e^{i \theta}$. $$z_{1}=e^{75^{\circ},}, z_{2}=e^{5^{\circ} i}$$
Complex Numbers and De Moivre's Theorem
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD