00:01
For this problem, we are asked to write that if z equals 1 over 2 plus 3 j plus 1 over 1 minus j squared, you must express z in the form a plus jb.
00:12
Now the first thing that i'll note here is 1 minus j squared is equal to 1 minus negative 1, which then will be equal to 2.
00:21
From that then, we'll have that we get z equals 1 over 2 plus 3 j plus 2.
00:29
Now we can get everything over a common denominator by multiplying through both sides by, oh actually, excuse me, i'll note a different thing that we can do here.
00:41
So we have that simplification.
00:43
The second term will go to 1 over 2.
00:45
What we can do with the other term is multiply by the conjugate.
00:49
So we have one times, or conjugate of the denominator, that is.
00:54
So we have 1 times 2 minus 3j over 2 minus 3j.
00:59
So in the numerator we'll now have 2 minus 3j, and in the denominator we'll get 13...